Convert BTU per pound Fahrenheit to Joule per gram Kelvin Online
About BTU per pound Fahrenheit to Joule per gram Kelvin Conversion
This converter converts BTU per pound Fahrenheit (BTU/lb·°F) to Joule per gram Kelvin (J/g·K). One BTU per pound Fahrenheit (BTU/lb·°F) equals 4.1868 Joule per gram Kelvin (J/g·K).
Formula:
1 BTU per pound Fahrenheit (BTU/lb·°F) = 4.1868 Joule per gram Kelvin (J/g·K)
Example:
1 BTU/lb·°F = 4.1868 J/g·K
2 BTU/lb·°F = 8.3736 J/g·K
BTU per pound Fahrenheit (BTU/lb·°F) to Joule per gram Kelvin (J/g·K) Conversion
BTU to Joule conversion explained with exact factors, step-by-step examples, and situations where this conversion is commonly used.
Conversion Formula
Joule = BTU × 4.1868
To convert BTU per pound Fahrenheit (BTU/lb·°F) to Joule per gram Kelvin (J/g·K), multiply the value by 4.1868. This factor is obtained by comparing their exact meter definitions.
Worked Example
Convert 1 BTU/lb.F to J/g.K.
- Step 1: Write the formula: J/g.K = BTU/lb.F × 4.1868
- Step 2: Substitute: 1 × 4.1868
- Step 3: Result: 4.1868 J/g.K
So, 1 BTU/lb.F = 4.1868 J/g.K.
About the Units
BTU per pound Fahrenheit (BTU/lb·°F)
One BTU per pound Fahrenheit (BTU/lb·°F) equals 4.1868 Joule per gram Kelvin (J/g·K)
A widely used unit across scientific, engineering, and measurement contexts.
Joule per gram Kelvin (J/g·K)
One Joule per gram Kelvin (J/g·K) equals 0.238846 BTU per pound Fahrenheit (BTU/lb·°F)
A widely used unit across scientific, engineering, and measurement contexts.
Where This Conversion Is Used
- Converting values from BTU to Joule for engineering or scientific workflows.
- Used when normalizing mixed-unit datasets requiring consistent Joule representation.
- Applied when comparing different measurement systems across tools and documents.
Frequently Asked Questions
How many Joule per gram Kelvin (J/g·K) are in 1 BTU per pound Fahrenheit (BTU/lb·°F)?
1 BTU/lb.F = 4.1868 J/g.K.
What is the formula for converting BTU per pound Fahrenheit (BTU/lb·°F) to Joule per gram Kelvin (J/g·K)?
Multiply the BTU/lb.F value by 4.1868.
Can I reverse the conversion?
Yes. 1 J/g.K = 0.238846 BTU/lb.F.
Conclusion
By applying the conversion factor shown above, you can reliably convert BTU per pound Fahrenheit (BTU/lb·°F) to Joule per gram Kelvin (J/g·K) for use in scientific analysis, engineering calculations, academic work, or daily measurements.
Quick Links for Unit Converters
Convert BTU per pound Fahrenheit to Other Units
1 BTU/lb.F = 4186.8 J/kg.K
1 BTU per pound Fahrenheit (BTU/lb·°F) = 4186.8 Joule per kilogram Kelvins (J/kg·K)
1 BTU/lb.F equals 4186.8 J/kg.Ks.
1 BTU/lb.F = 4186.8 J/kg.C
1 BTU per pound Fahrenheit (BTU/lb·°F) = 4186.8 Joule per kilogram Celsiuses (J/kg·°C)
1 BTU/lb.F equals 4186.8 J/kg.Cs.
1 BTU/lb.F = 4.1868 kJ/kg.K
1 BTU per pound Fahrenheit (BTU/lb·°F) = 4.1868 Kilojoule per kilogram Kelvins (kJ/kg·K)
1 BTU/lb.F equals 4.1868 kJ/kg.Ks.
1 BTU/lb.F = 1 cal/g.C
1 BTU per pound Fahrenheit (BTU/lb·°F) = 1 Calorie per gram Celsius (cal/g·°C)
1 BTU/lb.F equals 1 cal/g.C.
1 BTU/lb.F = 41868000 erg/g.K
1 BTU per pound Fahrenheit (BTU/lb·°F) = 41868000 Erg per gram Kelvins (erg/g·K)
1 BTU/lb.F equals 41868000 erg/g.Ks.
1 BTU/lb.F = 3258.03263635444 ft.lb/lb.F
1 BTU per pound Fahrenheit (BTU/lb·°F) = 3258.03263635444 Foot-pound per pound Fahrenheits (ft·lb/lb·°F)
1 BTU/lb.F equals 3258.03263635444 ft.lb/lb.ves.
1 BTU/lb.F = 1 kcal/kg.K
1 BTU per pound Fahrenheit (BTU/lb·°F) = 1 Kilocalorie per kilogram Kelvin (kcal/kg·K)
1 BTU/lb.F equals 1 kcal/kg.K.
1 BTU/lb.F = 4.1868 J/g.K
1 BTU per pound Fahrenheit (BTU/lb·°F) = 4.1868 Joule per gram Kelvins (J/g·K)
1 BTU/lb.F equals 4.1868 J/g.Ks.
Convert Joule per gram Kelvin to Other Units
1 J/g.K = 1000 J/kg.K
1 Joule per gram Kelvin (J/g·K) = 1000 Joule per kilogram Kelvins (J/kg·K)
1 J/g.K equals 1000 J/kg.Ks.
1 J/g.K = 1000 J/kg.C
1 Joule per gram Kelvin (J/g·K) = 1000 Joule per kilogram Celsiuses (J/kg·°C)
1 J/g.K equals 1000 J/kg.Cs.
1 J/g.K = 1 kJ/kg.K
1 Joule per gram Kelvin (J/g·K) = 1 Kilojoule per kilogram Kelvin (kJ/kg·K)
1 J/g.K equals 1 kJ/kg.K.
1 J/g.K = 0.23884589662749592 cal/g.C
1 Joule per gram Kelvin (J/g·K) = 0.23884589662749592 Calorie per gram Celsius (cal/g·°C)
1 J/g.K equals 0.23884589662749592 cal/g.C.
1 J/g.K = 10000000 erg/g.K
1 Joule per gram Kelvin (J/g·K) = 10000000 Erg per gram Kelvins (erg/g·K)
1 J/g.K equals 10000000 erg/g.Ks.
1 J/g.K = 0.23884589662749592 BTU/lb.F
1 Joule per gram Kelvin (J/g·K) = 0.23884589662749592 BTU per pound Fahrenheit (BTU/lb·°F)
1 J/g.K equals 0.23884589662749592 BTU/lb.F.
1 J/g.K = 778.1677262717207 ft.lb/lb.F
1 Joule per gram Kelvin (J/g·K) = 778.1677262717207 Foot-pound per pound Fahrenheits (ft·lb/lb·°F)
1 J/g.K equals 778.1677262717207 ft.lb/lb.ves.
1 J/g.K = 0.23884589662749592 kcal/kg.K
1 Joule per gram Kelvin (J/g·K) = 0.23884589662749592 Kilocalorie per kilogram Kelvin (kcal/kg·K)
1 J/g.K equals 0.23884589662749592 kcal/kg.K.