Convert BTU to Kilojoule using the exact conversion factor. This page provides the formula, reference values, and practical context for engineering, technical calculations, and professional measurement use.
BTU per pound Fahrenheit (BTU/lb·°F) = Kilojoule per kilogram Kelvin (kJ/kg·K) × 4.1868
To convert BTU per pound Fahrenheit (BTU/lb·°F) to Kilojoule per kilogram Kelvin (kJ/kg·K), multiply the value by 4.1868. The conversion factor is based on standardized unit definitions and is suitable for engineering analysis, system design, and professional measurement workflows.
Convert 1 BTU/lb.F to kJ/kg.K.
So, 1 BTU/lb.F = 4.1868 kJ/kg.K.
One BTU per pound Fahrenheit (BTU/lb·°F) equals 4.1868 Kilojoules per kilogram Kelvin (kJ/kg·K)
Units of specific heat capacity are standardized measurements used to quantify heat required to change a substance’s temperature.
One Kilojoule per kilogram Kelvin (kJ/kg·K) equals 4.1868 BTUs per pound Fahrenheit (BTU/lb·°F)
Units of specific heat capacity are standardized measurements used to quantify heat required to change a substance’s temperature.
How many Kilojoule per kilogram Kelvin (kJ/kg·K) are in 1 BTU per pound Fahrenheit (BTU/lb·°F)?
1 BTU per pound Fahrenheit (BTU/lb·°F) = 4.1868 Kilojoules per kilogram Kelvin (kJ/kg·K).
How many Kilojoule per kilogram Kelvin (kJ/kg·K) are in one BTU per pound Fahrenheit (BTU/lb·°F)?
One BTU per pound Fahrenheit (BTU/lb·°F) equals 4.1868 Kilojoules per kilogram Kelvin (kJ/kg·K).
How many kJ/kg.K are in one BTU/lb.F?
One BTU/lb.F equals 4.1868 kJ/kg.K.
What is the formula for converting BTU per pound Fahrenheit (BTU/lb·°F) to Kilojoule per kilogram Kelvin (kJ/kg·K)?
Multiply the BTU per pound Fahrenheit (BTU/lb·°F) value by 4.1868.
Can I reverse the conversion?
Yes. 1 Kilojoules per kilogram Kelvin (kJ/kg·K) = 0.238846 BTU per pound Fahrenheit (BTU/lb·°F).
Is this BTU per pound Fahrenheit (BTU/lb·°F) to Kilojoule per kilogram Kelvin (kJ/kg·K) conversion accurate for engineering use?
Yes. The conversion uses a standardized conversion factor suitable for engineering calculations, technical analysis, and professional reference.
Can this conversion be used for scientific or technical calculations?
Yes. This conversion is appropriate for scientific analysis, engineering calculations, simulations, and technical documentation where unit consistency is required.
By applying the conversion factor shown above, you can reliably convert BTU per pound Fahrenheit (BTU/lb·°F) to Kilojoule per kilogram Kelvin (kJ/kg·K) for thermal analysis, material comparison, and energy system design where accurate heat capacity values are required.
1 BTU/lb.F = 4,186.8 J/kg.K
1 BTU per pound Fahrenheit (BTU/lb·°F) = 4,186.8 Joules per kilogram Kelvin (J/kg·K)
One BTU per pound Fahrenheit (BTU/lb·°F) equals 4,186.8 Joules per kilogram Kelvin (J/kg·K)
1 BTU/lb.F = 4,186.8 J/kg.C
1 BTU per pound Fahrenheit (BTU/lb·°F) = 4,186.8 Joules per kilogram Celsius (J/kg·°C)
One BTU per pound Fahrenheit (BTU/lb·°F) equals 4,186.8 Joules per kilogram Celsius (J/kg·°C)
1 BTU/lb.F = 4.1868 kJ/kg.K
1 BTU per pound Fahrenheit (BTU/lb·°F) = 4.1868 Kilojoules per kilogram Kelvin (kJ/kg·K)
One BTU per pound Fahrenheit (BTU/lb·°F) equals 4.1868 Kilojoules per kilogram Kelvin (kJ/kg·K)
1 BTU/lb.F = 1 cal/g.C
1 BTU per pound Fahrenheit (BTU/lb·°F) = 1 Calorie per gram Celsius (cal/g·°C)
One BTU per pound Fahrenheit (BTU/lb·°F) equals 1 Calorie per gram Celsius (cal/g·°C)
1 BTU/lb.F = 4.1868 × 10⁷ erg/g.K
1 BTU per pound Fahrenheit (BTU/lb·°F) = 4.1868 × 10⁷ Ergs per gram Kelvin (erg/g·K)
One BTU per pound Fahrenheit (BTU/lb·°F) equals 4.1868 × 10⁷ Ergs per gram Kelvin (erg/g·K)
1 BTU/lb.F = 778.16933 ft.lb/lb.F
1 BTU per pound Fahrenheit (BTU/lb·°F) = 778.16933 Foot-pounds per pound Fahrenheit (ft·lb/lb·°F)
One BTU per pound Fahrenheit (BTU/lb·°F) equals 778.16933 Foot-pounds per pound Fahrenheit (ft·lb/lb·°F)
1 BTU/lb.F = 1 kcal/kg.K
1 BTU per pound Fahrenheit (BTU/lb·°F) = 1 Kilocalorie per kilogram Kelvin (kcal/kg·K)
One BTU per pound Fahrenheit (BTU/lb·°F) equals 1 Kilocalorie per kilogram Kelvin (kcal/kg·K)
1 BTU/lb.F = 4.1868 J/g.K
1 BTU per pound Fahrenheit (BTU/lb·°F) = 4.1868 Joules per gram Kelvin (J/g·K)
One BTU per pound Fahrenheit (BTU/lb·°F) equals 4.1868 Joules per gram Kelvin (J/g·K)