Convert Foot-pound to Kilojoule using the exact conversion factor. This page provides the formula, reference values, and practical context for engineering, technical calculations, and professional measurement use.
Foot-pound per pound Fahrenheit (ft·lb/lb·°F) = Kilojoule per kilogram Kelvin (kJ/kg·K) × 0.00538
To convert Foot-pound per pound Fahrenheit (ft·lb/lb·°F) to Kilojoule per kilogram Kelvin (kJ/kg·K), multiply the value by 0.00538. The conversion factor is based on standardized unit definitions and is suitable for engineering analysis, system design, and professional measurement workflows.
Convert 1 ft.lb/lb.F to kJ/kg.K.
So, 1 ft.lb/lb.F = 0.00538 kJ/kg.K.
One Foot-pound per pound Fahrenheit (ft·lb/lb·°F) equals 0.00538 Kilojoule per kilogram Kelvin (kJ/kg·K)
Units of specific heat capacity are standardized measurements used to quantify heat required to change a substance’s temperature.
One Kilojoule per kilogram Kelvin (kJ/kg·K) equals 0.00538 Foot-pound per pound Fahrenheit (ft·lb/lb·°F)
Units of specific heat capacity are standardized measurements used to quantify heat required to change a substance’s temperature.
How many Kilojoule per kilogram Kelvin (kJ/kg·K) are in 1 Foot-pound per pound Fahrenheit (ft·lb/lb·°F)?
1 Foot-pound per pound Fahrenheit (ft·lb/lb·°F) = 0.00538 Kilojoule per kilogram Kelvin (kJ/kg·K).
How many Kilojoule per kilogram Kelvin (kJ/kg·K) are in one Foot-pound per pound Fahrenheit (ft·lb/lb·°F)?
One Foot-pound per pound Fahrenheit (ft·lb/lb·°F) equals 0.00538 Kilojoule per kilogram Kelvin (kJ/kg·K).
How many kJ/kg.K are in one ft.lb/lb.F?
One ft.lb/lb.F equals 0.00538 kJ/kg.K.
What is the formula for converting Foot-pound per pound Fahrenheit (ft·lb/lb·°F) to Kilojoule per kilogram Kelvin (kJ/kg·K)?
Multiply the Foot-pound per pound Fahrenheit (ft·lb/lb·°F) value by 0.00538.
Can I reverse the conversion?
Yes. 1 Kilojoule per kilogram Kelvin (kJ/kg·K) = 185.862551 Foot-pounds per pound Fahrenheit (ft·lb/lb·°F).
Is this Foot-pound per pound Fahrenheit (ft·lb/lb·°F) to Kilojoule per kilogram Kelvin (kJ/kg·K) conversion accurate for engineering use?
Yes. The conversion uses a standardized conversion factor suitable for engineering calculations, technical analysis, and professional reference.
Can this conversion be used for scientific or technical calculations?
Yes. This conversion is appropriate for scientific analysis, engineering calculations, simulations, and technical documentation where unit consistency is required.
By applying the conversion factor shown above, you can reliably convert Foot-pound per pound Fahrenheit (ft·lb/lb·°F) to Kilojoule per kilogram Kelvin (kJ/kg·K) for thermal analysis, material comparison, and energy system design where accurate heat capacity values are required.
1 ft.lb/lb.F = 5.38032 J/kg.K
1 Foot-pound per pound Fahrenheit (ft·lb/lb·°F) = 5.38032 Joules per kilogram Kelvin (J/kg·K)
One Foot-pound per pound Fahrenheit (ft·lb/lb·°F) equals 5.38032 Joules per kilogram Kelvin (J/kg·K)
1 ft.lb/lb.F = 5.38032 J/kg.C
1 Foot-pound per pound Fahrenheit (ft·lb/lb·°F) = 5.38032 Joules per kilogram Celsius (J/kg·°C)
One Foot-pound per pound Fahrenheit (ft·lb/lb·°F) equals 5.38032 Joules per kilogram Celsius (J/kg·°C)
1 ft.lb/lb.F = 0.00538 kJ/kg.K
1 Foot-pound per pound Fahrenheit (ft·lb/lb·°F) = 0.00538 Kilojoule per kilogram Kelvin (kJ/kg·K)
One Foot-pound per pound Fahrenheit (ft·lb/lb·°F) equals 0.00538 Kilojoule per kilogram Kelvin (kJ/kg·K)
1 ft.lb/lb.F = 0.00129 cal/g.C
1 Foot-pound per pound Fahrenheit (ft·lb/lb·°F) = 0.00129 Calorie per gram Celsius (cal/g·°C)
One Foot-pound per pound Fahrenheit (ft·lb/lb·°F) equals 0.00129 Calorie per gram Celsius (cal/g·°C)
1 ft.lb/lb.F = 53,803.2 erg/g.K
1 Foot-pound per pound Fahrenheit (ft·lb/lb·°F) = 53,803.2 Ergs per gram Kelvin (erg/g·K)
One Foot-pound per pound Fahrenheit (ft·lb/lb·°F) equals 53,803.2 Ergs per gram Kelvin (erg/g·K)
1 ft.lb/lb.F = 0.00129 BTU/lb.F
1 Foot-pound per pound Fahrenheit (ft·lb/lb·°F) = 0.00129 BTU per pound Fahrenheit (BTU/lb·°F)
One Foot-pound per pound Fahrenheit (ft·lb/lb·°F) equals 0.00129 BTU per pound Fahrenheit (BTU/lb·°F)
1 ft.lb/lb.F = 0.00129 kcal/kg.K
1 Foot-pound per pound Fahrenheit (ft·lb/lb·°F) = 0.00129 Kilocalorie per kilogram Kelvin (kcal/kg·K)
One Foot-pound per pound Fahrenheit (ft·lb/lb·°F) equals 0.00129 Kilocalorie per kilogram Kelvin (kcal/kg·K)
1 ft.lb/lb.F = 0.00538 J/g.K
1 Foot-pound per pound Fahrenheit (ft·lb/lb·°F) = 0.00538 Joule per gram Kelvin (J/g·K)
One Foot-pound per pound Fahrenheit (ft·lb/lb·°F) equals 0.00538 Joule per gram Kelvin (J/g·K)