Convert Joule to Calorie using the exact conversion factor. This page provides the formula, reference values, and practical context for engineering, technical calculations, and professional measurement use.
Joule per gram Kelvin (J/g·K) = Calorie per gram Celsius (cal/g·°C) × 0.238846
To convert Joule per gram Kelvin (J/g·K) to Calorie per gram Celsius (cal/g·°C), multiply the value by 0.238846. The conversion factor is based on standardized unit definitions and is suitable for engineering analysis, system design, and professional measurement workflows.
Convert 1 J/g.K to cal/g.C.
So, 1 J/g.K = 0.238846 cal/g.C.
One Joule per gram Kelvin (J/g·K) equals 0.238846 Calorie per gram Celsius (cal/g·°C)
Units of specific heat capacity are standardized measurements used to quantify heat required to change a substance’s temperature.
One Calorie per gram Celsius (cal/g·°C) equals 0.238846 Joule per gram Kelvin (J/g·K)
Units of specific heat capacity are standardized measurements used to quantify heat required to change a substance’s temperature.
How many Calorie per gram Celsius (cal/g·°C) are in 1 Joule per gram Kelvin (J/g·K)?
1 Joule per gram Kelvin (J/g·K) = 0.238846 Calorie per gram Celsius (cal/g·°C).
How many Calorie per gram Celsius (cal/g·°C) are in one Joule per gram Kelvin (J/g·K)?
One Joule per gram Kelvin (J/g·K) equals 0.238846 Calorie per gram Celsius (cal/g·°C).
How many cal/g.C are in one J/g.K?
One J/g.K equals 0.238846 cal/g.C.
What is the formula for converting Joule per gram Kelvin (J/g·K) to Calorie per gram Celsius (cal/g·°C)?
Multiply the Joule per gram Kelvin (J/g·K) value by 0.238846.
Can I reverse the conversion?
Yes. 1 Calorie per gram Celsius (cal/g·°C) = 4.1868 Joules per gram Kelvin (J/g·K).
Is this Joule per gram Kelvin (J/g·K) to Calorie per gram Celsius (cal/g·°C) conversion accurate for engineering use?
Yes. The conversion uses a standardized conversion factor suitable for engineering calculations, technical analysis, and professional reference.
Can this conversion be used for scientific or technical calculations?
Yes. This conversion is appropriate for scientific analysis, engineering calculations, simulations, and technical documentation where unit consistency is required.
By applying the conversion factor shown above, you can reliably convert Joule per gram Kelvin (J/g·K) to Calorie per gram Celsius (cal/g·°C) for thermal analysis, material comparison, and energy system design where accurate heat capacity values are required.
1 J/g.K = 1,000 J/kg.K
1 Joule per gram Kelvin (J/g·K) = 1,000 Joules per kilogram Kelvin (J/kg·K)
One Joule per gram Kelvin (J/g·K) equals 1,000 Joules per kilogram Kelvin (J/kg·K)
1 J/g.K = 1,000 J/kg.C
1 Joule per gram Kelvin (J/g·K) = 1,000 Joules per kilogram Celsius (J/kg·°C)
One Joule per gram Kelvin (J/g·K) equals 1,000 Joules per kilogram Celsius (J/kg·°C)
1 J/g.K = 1 kJ/kg.K
1 Joule per gram Kelvin (J/g·K) = 1 Kilojoule per kilogram Kelvin (kJ/kg·K)
One Joule per gram Kelvin (J/g·K) equals 1 Kilojoule per kilogram Kelvin (kJ/kg·K)
1 J/g.K = 0.23885 cal/g.C
1 Joule per gram Kelvin (J/g·K) = 0.23885 Calorie per gram Celsius (cal/g·°C)
One Joule per gram Kelvin (J/g·K) equals 0.23885 Calorie per gram Celsius (cal/g·°C)
1 J/g.K = 10⁷ erg/g.K
1 Joule per gram Kelvin (J/g·K) = 10⁷ Ergs per gram Kelvin (erg/g·K)
One Joule per gram Kelvin (J/g·K) equals 10⁷ Ergs per gram Kelvin (erg/g·K)
1 J/g.K = 0.23885 BTU/lb.F
1 Joule per gram Kelvin (J/g·K) = 0.23885 BTU per pound Fahrenheit (BTU/lb·°F)
One Joule per gram Kelvin (J/g·K) equals 0.23885 BTU per pound Fahrenheit (BTU/lb·°F)
1 J/g.K = 185.86255 ft.lb/lb.F
1 Joule per gram Kelvin (J/g·K) = 185.86255 Foot-pounds per pound Fahrenheit (ft·lb/lb·°F)
One Joule per gram Kelvin (J/g·K) equals 185.86255 Foot-pounds per pound Fahrenheit (ft·lb/lb·°F)
1 J/g.K = 0.23885 kcal/kg.K
1 Joule per gram Kelvin (J/g·K) = 0.23885 Kilocalorie per kilogram Kelvin (kcal/kg·K)
One Joule per gram Kelvin (J/g·K) equals 0.23885 Kilocalorie per kilogram Kelvin (kcal/kg·K)